Codesignal - centuryFromYear solution

Solution one:

Basic straight forward solution.

def centuryFromYear(year):
    if year % 100 == 0:
        return year // 100
    return (year // 100) + 1

Solution two:

Interesting solution without using else.

def centuryFromYear(year):
    return (year + 99) // 100

Solution three:

Same theory as above but using math library function.

def centuryFromYear(year):
    return math.ceil(year / 100)
}

Solution four:

An different math approach.

def centuryFromYear(year):
    return (year - 1) / 100 + 1;
}